A simple electric heater, which has efficiency greater than 1
Moderator: scott
re: A simple electric heater, which has efficiency greater t
COP = 1.37 <=> COP > 1. This is the reality.
Re: l'm drawing a blank
Then would I be guilty of felony stuipidity in the first degree, not to mention
various counts of fraud like you?
...................................................................................................................
....
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
this is a test
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
various counts of fraud like you?
...................................................................................................................
....
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
this is a test
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
- Attachments
-
- Scott should create a sub forum titled 'hell' & move your trolling blog thread & your needy butt both into it.
........................¯\_(ツ)_/¯
¯\_(ツ)_/¯ the future is here ¯\_(ツ)_/¯
Advocate of God Almighty, maker of heaven and earth and redeemer of my soul.
Walter Clarkson
© 2023 Walter W. Clarkson, LLC
All rights reserved. Do not even quote me w/o my expressed written consent.
¯\_(ツ)_/¯ the future is here ¯\_(ツ)_/¯
Advocate of God Almighty, maker of heaven and earth and redeemer of my soul.
Walter Clarkson
© 2023 Walter W. Clarkson, LLC
All rights reserved. Do not even quote me w/o my expressed written consent.
re: A simple electric heater, which has efficiency greater t
To WaltzCee.
==================
Where do you see any fraud in the text below?
======================================================
The text below is a copy of our post of April 13, 2021, 5:32 pm. (The text below has been published many times in this forum topic.)
----------------------------
Have a look again at the book "Solved Problems in Physics", 2004, Volume 2, p. 876, solved problem 12.97. The author of this book is Prof. S. L. Srivastava (Ph.D.)
The same book can be found at the link https://books.google.bg/books?id=rrKFzL ... 22&f=false
--------------------------
For your convenience I am giving below the text of the problem and its solution.
--------------------------
12.97. In the electrolysis of sulphuric acid solution, 100 mg of hydrogen is liberated in a period of 20 minutes. The resistance of the electrolyte is 0.5 Ohm. Calculate the power consumed. Electrochemical equivalent of hydrogen is 1.044 x 10 -8 kg/C.
SOLUTION.
Prof. S. L. Srivastava's solution is given below.
Prof. S. L. Srivastava's solution consists of two lines only.
LINE 1. Current through the electrolyte is given by I = (m)/(Z x t).
LINE 2. Power consumed = (I) x (I) x (R) = ((m)/(Z x t)) x ((m)/(Z x t)) x (R) = 31.86 W.
---------------------------
Prof. S. L. Srivastava stops here his calculations.
(The related solution's set of equations is not given here in order to save time and space. This set of equations however can be found in the book or in the link above.)
--------------------------
WE DEVELOPED FURTHER PROF. SRIVASTAVA'S SOLVED PROBLEM IN A NON-STANDARD MANNER.
OUR FURTHER DEVELOPMENT OF PROF. SRIVASTAVA'S SOLVED PROBLEM LED TO COP > 1.
HERE IS THE ESSENCE OF OUR APPROACH.
--------------------------
1) Let us calculate the inlet energy, that is, inlet energy = (31.86 W) x (1200 s) = 38232 Ws = 38232 J.
2) The Joule's heat, generated in the process of electrolysis is given by
Q = (I) x (I) x (R) x (t) = ((m)/(Z x t)) x ((m)/(Z x t)) x (R) x (t) = (31.86 W) x (1200 s) = 38232 Ws = 38232 J = outlet energy 1.
3) HHV of hydrogen is 142 000 000 J/kg. Therefore the heat H, generated by burning/exploding of 0.0001 kg of hydrogen, is given by
H = (HHV) x (m) = (142 000 000) x (0.0001) = 14200 J = outlet energy 2,
where
m = mass of the released hydrogen
HHV = higher heating value oh hydrogen
4) Therefore we can write down the equalities:
4A) outlet energy 1 + outlet energy 2 = 38232 J + 14200 J = 52432 J
4B) inlet energy = 38232 J.
5) Therefore COP is given by
COP = 52432 J/38232 J = 1.37 <=> COP = 1.37 <=> COP > 1.
------------------------------
IMPORTANT NOTE. Constant pure water and cooling agent supply could keep constant the electrolyte's temperature, heat exchange, mass and ohmic resistance, respectively. Besides 0.0001 kg of hydrogen (and the related amount of the already split pure water) is small enough and can be neglected as a factor influencing the electrolyte's temperature, mass and ohmic resisitance.
-----------------------------
And one more interesting fact.
Literally the same solved problem can be found in an old Russian (still from the Soviet times) book "Сборник задач и вопросов по физике", 1986, p. 130, solved example problem 71. The authors of this book are Р. А. Гладкова and Н. И. Кутиловская. In the Russian version the data is a little different, that is, time is 25 minutes, the amount of generated hydrogen is 150 mg, Ohmic resisitance is 0.4 Ohm and the calculated power is 37 W.
Russians also stopped their calculations at 37 W.
Our further development of the Russian version led to the same COP = 1.37, that is, we have again the same COP > 1.
==============================
I am asking my question for the 1st time: Where do you see any fraud in the text above?
I am looking forward to your answer for the 1st time.
==================
Where do you see any fraud in the text below?
======================================================
The text below is a copy of our post of April 13, 2021, 5:32 pm. (The text below has been published many times in this forum topic.)
----------------------------
Have a look again at the book "Solved Problems in Physics", 2004, Volume 2, p. 876, solved problem 12.97. The author of this book is Prof. S. L. Srivastava (Ph.D.)
The same book can be found at the link https://books.google.bg/books?id=rrKFzL ... 22&f=false
--------------------------
For your convenience I am giving below the text of the problem and its solution.
--------------------------
12.97. In the electrolysis of sulphuric acid solution, 100 mg of hydrogen is liberated in a period of 20 minutes. The resistance of the electrolyte is 0.5 Ohm. Calculate the power consumed. Electrochemical equivalent of hydrogen is 1.044 x 10 -8 kg/C.
SOLUTION.
Prof. S. L. Srivastava's solution is given below.
Prof. S. L. Srivastava's solution consists of two lines only.
LINE 1. Current through the electrolyte is given by I = (m)/(Z x t).
LINE 2. Power consumed = (I) x (I) x (R) = ((m)/(Z x t)) x ((m)/(Z x t)) x (R) = 31.86 W.
---------------------------
Prof. S. L. Srivastava stops here his calculations.
(The related solution's set of equations is not given here in order to save time and space. This set of equations however can be found in the book or in the link above.)
--------------------------
WE DEVELOPED FURTHER PROF. SRIVASTAVA'S SOLVED PROBLEM IN A NON-STANDARD MANNER.
OUR FURTHER DEVELOPMENT OF PROF. SRIVASTAVA'S SOLVED PROBLEM LED TO COP > 1.
HERE IS THE ESSENCE OF OUR APPROACH.
--------------------------
1) Let us calculate the inlet energy, that is, inlet energy = (31.86 W) x (1200 s) = 38232 Ws = 38232 J.
2) The Joule's heat, generated in the process of electrolysis is given by
Q = (I) x (I) x (R) x (t) = ((m)/(Z x t)) x ((m)/(Z x t)) x (R) x (t) = (31.86 W) x (1200 s) = 38232 Ws = 38232 J = outlet energy 1.
3) HHV of hydrogen is 142 000 000 J/kg. Therefore the heat H, generated by burning/exploding of 0.0001 kg of hydrogen, is given by
H = (HHV) x (m) = (142 000 000) x (0.0001) = 14200 J = outlet energy 2,
where
m = mass of the released hydrogen
HHV = higher heating value oh hydrogen
4) Therefore we can write down the equalities:
4A) outlet energy 1 + outlet energy 2 = 38232 J + 14200 J = 52432 J
4B) inlet energy = 38232 J.
5) Therefore COP is given by
COP = 52432 J/38232 J = 1.37 <=> COP = 1.37 <=> COP > 1.
------------------------------
IMPORTANT NOTE. Constant pure water and cooling agent supply could keep constant the electrolyte's temperature, heat exchange, mass and ohmic resistance, respectively. Besides 0.0001 kg of hydrogen (and the related amount of the already split pure water) is small enough and can be neglected as a factor influencing the electrolyte's temperature, mass and ohmic resisitance.
-----------------------------
And one more interesting fact.
Literally the same solved problem can be found in an old Russian (still from the Soviet times) book "Сборник задач и вопросов по физике", 1986, p. 130, solved example problem 71. The authors of this book are Р. А. Гладкова and Н. И. Кутиловская. In the Russian version the data is a little different, that is, time is 25 minutes, the amount of generated hydrogen is 150 mg, Ohmic resisitance is 0.4 Ohm and the calculated power is 37 W.
Russians also stopped their calculations at 37 W.
Our further development of the Russian version led to the same COP = 1.37, that is, we have again the same COP > 1.
==============================
I am asking my question for the 1st time: Where do you see any fraud in the text above?
I am looking forward to your answer for the 1st time.
re: A simple electric heater, which has efficiency greater t
sudo shutdown now
re: A simple electric heater, which has efficiency greater t
To Tarsier79.
=====================
Did you take your medicine this morning?:) No? Take it immediately! And don't forget -- double dose!:)
=====================
Did you take your medicine this morning?:) No? Take it immediately! And don't forget -- double dose!:)
re: A simple electric heater, which has efficiency greater t
To WaltzCee.
==================
Asking my question for the 2nd time: Where do you see any fraud in the text below?
Looking forward to your answer for the 2nd time.
======================================================
The text below is a copy of our post of April 13, 2021, 5:32 pm. (The text below has been published many times in this forum topic.)
----------------------------
Have a look again at the book "Solved Problems in Physics", 2004, Volume 2, p. 876, solved problem 12.97. The author of this book is Prof. S. L. Srivastava (Ph.D.)
The same book can be found at the link https://books.google.bg/books?id=rrKFzL ... 22&f=false
--------------------------
For your convenience I am giving below the text of the problem and its solution.
--------------------------
12.97. In the electrolysis of sulphuric acid solution, 100 mg of hydrogen is liberated in a period of 20 minutes. The resistance of the electrolyte is 0.5 Ohm. Calculate the power consumed. Electrochemical equivalent of hydrogen is 1.044 x 10 -8 kg/C.
SOLUTION.
Prof. S. L. Srivastava's solution is given below.
Prof. S. L. Srivastava's solution consists of two lines only.
LINE 1. Current through the electrolyte is given by I = (m)/(Z x t).
LINE 2. Power consumed = (I) x (I) x (R) = ((m)/(Z x t)) x ((m)/(Z x t)) x (R) = 31.86 W.
---------------------------
Prof. S. L. Srivastava stops here his calculations.
(The related solution's set of equations is not given here in order to save time and space. This set of equations however can be found in the book or in the link above.)
--------------------------
WE DEVELOPED FURTHER PROF. SRIVASTAVA'S SOLVED PROBLEM IN A NON-STANDARD MANNER.
OUR FURTHER DEVELOPMENT OF PROF. SRIVASTAVA'S SOLVED PROBLEM LED TO COP > 1.
HERE IS THE ESSENCE OF OUR APPROACH.
--------------------------
1) Let us calculate the inlet energy, that is, inlet energy = (31.86 W) x (1200 s) = 38232 Ws = 38232 J.
2) The Joule's heat, generated in the process of electrolysis is given by
Q = (I) x (I) x (R) x (t) = ((m)/(Z x t)) x ((m)/(Z x t)) x (R) x (t) = (31.86 W) x (1200 s) = 38232 Ws = 38232 J = outlet energy 1.
3) HHV of hydrogen is 142 000 000 J/kg. Therefore the heat H, generated by burning/exploding of 0.0001 kg of hydrogen, is given by
H = (HHV) x (m) = (142 000 000) x (0.0001) = 14200 J = outlet energy 2,
where
m = mass of the released hydrogen
HHV = higher heating value oh hydrogen
4) Therefore we can write down the equalities:
4A) outlet energy 1 + outlet energy 2 = 38232 J + 14200 J = 52432 J
4B) inlet energy = 38232 J.
5) Therefore COP is given by
COP = 52432 J/38232 J = 1.37 <=> COP = 1.37 <=> COP > 1.
------------------------------
IMPORTANT NOTE. Constant pure water and cooling agent supply could keep constant the electrolyte's temperature, heat exchange, mass and ohmic resistance, respectively. Besides 0.0001 kg of hydrogen (and the related amount of the already split pure water) is small enough and can be neglected as a factor influencing the electrolyte's temperature, mass and ohmic resisitance.
-----------------------------
And one more interesting fact.
Literally the same solved problem can be found in an old Russian (still from the Soviet times) book "Сборник задач и вопросов по физике", 1986, p. 130, solved example problem 71. The authors of this book are Р. А. Гладкова and Н. И. Кутиловская. In the Russian version the data is a little different, that is, time is 25 minutes, the amount of generated hydrogen is 150 mg, Ohmic resisitance is 0.4 Ohm and the calculated power is 37 W.
Russians also stopped their calculations at 37 W.
Our further development of the Russian version led to the same COP = 1.37, that is, we have again the same COP > 1.
==============================
Asking my question for the 2nd time: Where do you see any fraud in the text above?
Looking forward to your answer for the 2nd time.
==================
Asking my question for the 2nd time: Where do you see any fraud in the text below?
Looking forward to your answer for the 2nd time.
======================================================
The text below is a copy of our post of April 13, 2021, 5:32 pm. (The text below has been published many times in this forum topic.)
----------------------------
Have a look again at the book "Solved Problems in Physics", 2004, Volume 2, p. 876, solved problem 12.97. The author of this book is Prof. S. L. Srivastava (Ph.D.)
The same book can be found at the link https://books.google.bg/books?id=rrKFzL ... 22&f=false
--------------------------
For your convenience I am giving below the text of the problem and its solution.
--------------------------
12.97. In the electrolysis of sulphuric acid solution, 100 mg of hydrogen is liberated in a period of 20 minutes. The resistance of the electrolyte is 0.5 Ohm. Calculate the power consumed. Electrochemical equivalent of hydrogen is 1.044 x 10 -8 kg/C.
SOLUTION.
Prof. S. L. Srivastava's solution is given below.
Prof. S. L. Srivastava's solution consists of two lines only.
LINE 1. Current through the electrolyte is given by I = (m)/(Z x t).
LINE 2. Power consumed = (I) x (I) x (R) = ((m)/(Z x t)) x ((m)/(Z x t)) x (R) = 31.86 W.
---------------------------
Prof. S. L. Srivastava stops here his calculations.
(The related solution's set of equations is not given here in order to save time and space. This set of equations however can be found in the book or in the link above.)
--------------------------
WE DEVELOPED FURTHER PROF. SRIVASTAVA'S SOLVED PROBLEM IN A NON-STANDARD MANNER.
OUR FURTHER DEVELOPMENT OF PROF. SRIVASTAVA'S SOLVED PROBLEM LED TO COP > 1.
HERE IS THE ESSENCE OF OUR APPROACH.
--------------------------
1) Let us calculate the inlet energy, that is, inlet energy = (31.86 W) x (1200 s) = 38232 Ws = 38232 J.
2) The Joule's heat, generated in the process of electrolysis is given by
Q = (I) x (I) x (R) x (t) = ((m)/(Z x t)) x ((m)/(Z x t)) x (R) x (t) = (31.86 W) x (1200 s) = 38232 Ws = 38232 J = outlet energy 1.
3) HHV of hydrogen is 142 000 000 J/kg. Therefore the heat H, generated by burning/exploding of 0.0001 kg of hydrogen, is given by
H = (HHV) x (m) = (142 000 000) x (0.0001) = 14200 J = outlet energy 2,
where
m = mass of the released hydrogen
HHV = higher heating value oh hydrogen
4) Therefore we can write down the equalities:
4A) outlet energy 1 + outlet energy 2 = 38232 J + 14200 J = 52432 J
4B) inlet energy = 38232 J.
5) Therefore COP is given by
COP = 52432 J/38232 J = 1.37 <=> COP = 1.37 <=> COP > 1.
------------------------------
IMPORTANT NOTE. Constant pure water and cooling agent supply could keep constant the electrolyte's temperature, heat exchange, mass and ohmic resistance, respectively. Besides 0.0001 kg of hydrogen (and the related amount of the already split pure water) is small enough and can be neglected as a factor influencing the electrolyte's temperature, mass and ohmic resisitance.
-----------------------------
And one more interesting fact.
Literally the same solved problem can be found in an old Russian (still from the Soviet times) book "Сборник задач и вопросов по физике", 1986, p. 130, solved example problem 71. The authors of this book are Р. А. Гладкова and Н. И. Кутиловская. In the Russian version the data is a little different, that is, time is 25 minutes, the amount of generated hydrogen is 150 mg, Ohmic resisitance is 0.4 Ohm and the calculated power is 37 W.
Russians also stopped their calculations at 37 W.
Our further development of the Russian version led to the same COP = 1.37, that is, we have again the same COP > 1.
==============================
Asking my question for the 2nd time: Where do you see any fraud in the text above?
Looking forward to your answer for the 2nd time.
re: A simple electric heater, which has efficiency greater t
I understand that Scott does not remove you from the forum, but without removing you we could restrict you to once a month, which is more than enough for people who have never done anything with their 10 fingers and are off topic concerning Bessler... You study Beesler, find us the right page and we'll talk again.
"Have a look again at the book "Solved Problems in Physics", 2004, Volume 2, p. 876, solved problem 12.97. The author of this book is Prof. S. L. Srivastava (Ph.D.)", even the Russians don't believe in it... :)
Very easy nowadays to make a model.
https://youtu.be/4fC6SA8Zo04
Off topic at this point it's obscene, Maybe suggest to Scott to place you in the "off topic" de facto section.
A++
"Have a look again at the book "Solved Problems in Physics", 2004, Volume 2, p. 876, solved problem 12.97. The author of this book is Prof. S. L. Srivastava (Ph.D.)", even the Russians don't believe in it... :)
Very easy nowadays to make a model.
https://youtu.be/4fC6SA8Zo04
Off topic at this point it's obscene, Maybe suggest to Scott to place you in the "off topic" de facto section.
A++
Not everything I present is functional, but a surprise can't be completely ruled out.Greetings.
re: A simple electric heater, which has efficiency greater t
But... Isn't it more effective to completely ignore his messages ?
re: A simple electric heater, which has efficiency greater t
It's like seeing a train wreck, unstable. You know there's going to be some seriously
ugly mahaim but you still can't resist watching.
ugly mahaim but you still can't resist watching.
........................¯\_(ツ)_/¯
¯\_(ツ)_/¯ the future is here ¯\_(ツ)_/¯
Advocate of God Almighty, maker of heaven and earth and redeemer of my soul.
Walter Clarkson
© 2023 Walter W. Clarkson, LLC
All rights reserved. Do not even quote me w/o my expressed written consent.
¯\_(ツ)_/¯ the future is here ¯\_(ツ)_/¯
Advocate of God Almighty, maker of heaven and earth and redeemer of my soul.
Walter Clarkson
© 2023 Walter W. Clarkson, LLC
All rights reserved. Do not even quote me w/o my expressed written consent.
re: A simple electric heater, which has efficiency greater t
To thx4, unstable and WaltzCee.
--------------------------------------------
But why do you always avoid to answer my clear and simple questions? This is not an honest discussion.
--------------------------------------------
But why do you always avoid to answer my clear and simple questions? This is not an honest discussion.
re: A simple electric heater, which has efficiency greater t
This is not an honest discussion.
Agreed.
re: A simple electric heater, which has efficiency greater t
To Tarsier79.
-------------------------------
I should like to pose the same question to you: Why do you always avoid to answer my clear and simple questions by using only either "yes" or "no"? Is this your personal example of honest behaviour and honest approach?
-------------------------------
I should like to pose the same question to you: Why do you always avoid to answer my clear and simple questions by using only either "yes" or "no"? Is this your personal example of honest behaviour and honest approach?
re: A simple electric heater, which has efficiency greater t
You are not interested in proper conversation. You have already been shown why both of your theories here are flawed, yet you keep asking the same question. You still have the same repeating and circular arguments, reactions and process, just like a bot.
re: A simple electric heater, which has efficiency greater t
Pete doesn't seem to pass the Turing test.
........................¯\_(ツ)_/¯
¯\_(ツ)_/¯ the future is here ¯\_(ツ)_/¯
Advocate of God Almighty, maker of heaven and earth and redeemer of my soul.
Walter Clarkson
© 2023 Walter W. Clarkson, LLC
All rights reserved. Do not even quote me w/o my expressed written consent.
¯\_(ツ)_/¯ the future is here ¯\_(ツ)_/¯
Advocate of God Almighty, maker of heaven and earth and redeemer of my soul.
Walter Clarkson
© 2023 Walter W. Clarkson, LLC
All rights reserved. Do not even quote me w/o my expressed written consent.
re: A simple electric heater, which has efficiency greater t
To Tarsier79 and to WaltzCee.
==================
Hi paid agents of the official science mafia,
1) You are simply two clumsy manipulators and this is already more than evident for all honest members of this forum. Because if your answer is "no", then you would smash to smithereens the basic axioms of standard electric engineering. And if your answer is "yes", then you would admit the validity of our OU water-splitting electrolysis effect.
2) Your primitive manipulation techniques do not give any result, this is more than evident. Take some beginner's manipulation techniques guide and study it very, very carefully. Because otherwise you both simply resemble two clumsy clowns!
3) You fail again to manipulate successfully the audience! Your masters will not pay you your month's salary! Your masters will beat you! You have to run quickly!:)
==================
Hi paid agents of the official science mafia,
1) You are simply two clumsy manipulators and this is already more than evident for all honest members of this forum. Because if your answer is "no", then you would smash to smithereens the basic axioms of standard electric engineering. And if your answer is "yes", then you would admit the validity of our OU water-splitting electrolysis effect.
2) Your primitive manipulation techniques do not give any result, this is more than evident. Take some beginner's manipulation techniques guide and study it very, very carefully. Because otherwise you both simply resemble two clumsy clowns!
3) You fail again to manipulate successfully the audience! Your masters will not pay you your month's salary! Your masters will beat you! You have to run quickly!:)