BesslerWheel.com

[Besslers Assistant]

Pleasant greeting to all,

I am hoping this time it is really solved. With this new and very simple device I believe the Bessler Wheel has been solved. Although the idea is simple, it takes a lot of explanation for it to be fully understood and I hope you understand me.



First picture figure 1, the device is basically one tube (that is full with air) inside another tube (filled with water). The construction denotes its operation, so figure 2 shows (by colors) the different parts. The green and blue are the inside and outside tubes respectively. The pink is a handle (could be another tube or solid material) for the inside tube. This handle fits inside a smaller tube, which is purple; this smaller tube is the handle for the outer tube. This arrangement will give the inner tube free movement to that of the outer tube. Using the tubing of a bicycle tire ( or any rubber tube that can do the job) you create a seal from the base of the pink handle, over the pink handle and folded back and connected to the inside base of the purple handle. This connection will create an effective seal and still allow free movement of the inner tube.
The third figure shows two of these devices one above the other. The pink handles are connected together and the outer tubes are fixed and fastened to the frame that is holding it. This will allow the inner tubes of both devices to move up and down freely. When the outer tube is filled with water it will allow the inner tubes to go up, this will cause the remaining water to go to the bottom (which I labeled base). This cause the device to be bottom heavy, but as ‘they’ say nothing is truly free. You must trade movement for weight, for the more movement you get going up and down the more bottom heavy the device will be. But the device can be optimized. But, also, if you design this device differently and connect it to some of the other ideas of this forum, you will have many different kinds of Bessler wheels. Because this device behaves opposite to gravity. Gravity pulls down all the time, buoyancy seeks to go up all the time.


Now, the calculations: First I most apologize to daxwc, I said PVC was light but it is not (maybe to other things).

I apologize Daxwc for my comments earlier.

My calculations will show how heavy PVC really is. If anyone knows of lighter, cheaper and stronger tubing let us know. The device has an inner tube of 12.7cm (5inch) by 76 cm (~2.5 ft) and an outer tube of 15.2 cm (6inch) by 96.5 cm (~3ft, 2 inch). This will allow a movement of 15 cm (~6 inch).
The buoyancy o f the inner tube is = the density of water * gravity * volume of object. = 1000*9.8*(0.127/2) ^2*pi*0.76 = 94.3 N (21.2 lbs)
The weight of my inner tube is = length of tube * weight per length of tube = 2.5 ft * 2.73 lb/ft= 6.825 lbs (30.3 N).
I will add 20%, because of the weight of the handle and tube caps, so the total weight is = 6.825 * 1.2 = 8.2 lbs. (36.36 N)
So you will have a force of (21.2 – 8.2) 13 lbs moved 6 inches or (94.3 -36.36) ~58 N moved 15.2 cm.
Remember you have two of these device, one above the other and you have the water at the base to counter act. The weight at the base will be = inside diameter of the outer tube * the height of movement. So we have = (.15/2)^2*pi*0.15*1000*9.8 = ~26 N (5.8 lbs)
If I add an extra 2.54 cm (1 inch) height for error correction, it will give = ~31.8 N (7.1 lbs)


You can use this force anyway you see fit to create a Bessler wheel. I like path_finder A.



It is simple and very effective. At the horizontal position (zero degrees) you need very little effort to pull one weight in and push the other weight out. So any extra force you have can used by changing the alignment angle of the both A’s. Since we have a 6 inch lift ( 3 inch above the horizontal and 3 inch below) the two A’s will cause motion.



Tell me what you think.
Bye for now.

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[Tarsier79]

You are making the mistake of thinking buoyancy isn't gravity driven. Your buoyancy mechanism is giving you an equal opposite force, but with added lag of the viscosity of the water as that of a simple weight driven mechanism.
As your water flows to the bottom, how much effort will it take to flip your force mechanism over? The same amount you get from the buoyancy.

[Besslers Assistant]

@Tarsier79 , Buoyancy is technically gravity driven, but it is more likely that gravity orients buoyancy. The substances in this gravity field orients themselves by there respective densities.
A balloon has more lifting force in 100 ft of water to that of a 100ft of air. it is because the water pushes it up, but the water cannot push itself down, because it is already at the bottom. So the balloon will get all the force, it is the same in the mechanism, because it is on the ground. I do not understand your viscosity comment, I am moving 6 inches and water is very thin, it will not take a long time for the inner tube to reach the top. The mechanism is bottom heavy, but not overtly so, I included the weight of the water in my calculations, it is about 7.1 lbs. But the mechanism can lift 13 lbs 6 inches high. However one of the 13 lb weight can swing out three inches above the horizontal, while the other 13 lb weight swings in from the outer rim to a point near the axle from three inches below the horizontal. So we have a 13 lb weight near the axle , and another one about 4 degree above the horizontal and a 7.1 lb weight at the 270 degree position. The 13 lb weight will swing to the other side like a pendulum, but when it reaches the 4 degree mark below the horizontal the mechanism will trigger again. The 8 degrees of energy would be save as momentum, but the axle friction would take some, but it will revolve. Remember Bessler said that one bar of his machine can hardly turn itself , but it turned.

If you do my calculations for a 1/8 wedge of a 6.5 ft wheel moving the same 6 inches, you will be very surprise at what force you find. But I will leave that duty for someone else to post.

bye for now.

[preoccupied]

I think those pictures are super cool.