Forum Index
BesslerWheel.com
Discussion Board

Log inLog in RegisterRegister SearchSearch BlogsBlogs Blog NewsBlog News PollsPolls FAQFAQ FAQWiki
Forum Index
Oxygons Earth Day PMM

 
Page 5 of 5 Goto page Previous  1, 2, 3, 4, 5
Post new topic   Reply to topic    Forum Index -> General Discussion
View previous topic :: View next topic  
Author Message
joeuser
Dabbler
Dabbler

Joined: 28 Jun 2006
Posts: 2
Total Words: 0


Reputation: None
None  
PostPosted: Wed Jun 28, 2006 10:46 pm    Post subject: re: Oxygons Earth Day PMM Reply with quote

I'm starting to question what I said about the gas...

If you have gas in a sealed chamber and you want to move that gas from the top of the sealed chamber to the bottom... would it matter if the chamber was submerged in water or not? Does a gas become more buoyant the deeper it is submerged in water? I'm not sure...


Back to top
View user's profile
ken_behrendt
Addict
Addict

Joined: 02 Mar 2005
Posts: 3487
Total Words: 948,144
Location: new jersey, usa

Reputation: Respected
Respected  
PostPosted: Thu Jun 29, 2006 3:04 pm    Post subject: re: Oxygons Earth Day PMM

joeuser...

The buoyant forces acting on a submerged body do not change that much with depth due to the very low compressibility of liquids. They depend only on the weight of the volume of water displaced as the object is submerged.

However, the pressure acting on a submerged body definitely increases dramatically with depth. For every approximtely 32 feet deeper an object is submerged, the average pressure acting on its external surfaces will increase by about 14.7 lbs per square inch. That works out to over 2100 lbs per square foot!

At a depth of 320 feet, the external pressure of the water will be about 147 lbs per square inch or 21,000 lbs per square foot. To prevent his internal body cavities from being crushed by the external water pressure at a depth of 320 feet, a skin diver must breath air from a tank with the same pressure as the water he is immersed in.


ken



_________________
On 7/6/06, I found, in any overbalanced gravity wheel with rotation rate, ω, axle to CG distance d, and CG dip angle φ, the average vertical velocity of its drive weights is downward and given by:

Vaver = -2(√2)πdωcosφ
Back to top
View user's profile Send email Visit poster's website
Display posts from previous:   
Post new topic  Reply to topic    Forum Index -> General Discussion All times are GMT
Page 5 of 5 Goto page Previous  1, 2, 3, 4, 5


 
Jump to:   
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You can vote in polls in this forum
You cannot attach files in this forum
You can download files in this forum

Log in:         Remember me     

Please click below to help support this website!

Google