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A binary solution ?!...

 
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path_finder
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PostPosted: Wed Jun 20, 2012 5:59 pm    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

Dear jacob alex,
you wrote:
a)-long arm into a short arm,in the bottom point
b)-short arm into a long arm in the top point

That's the Botafumeiro principle:
http://www.sciences.univ-nantes.fr/physique/perso/gtulloue/Meca/Oscillateurs/botafumeiro.html
On a pure physical point of view this is named 'the parametric pendulum'.



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PostPosted: Wed Jun 20, 2012 8:11 pm    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

Botafumeiro is a clever old device!

Would be great if the eccentric auxiliary wheel set could send elongation exactly at straight point.

This 'coincidence' is what makes botafum not linear and with strange reaction.


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PostPosted: Wed Jun 20, 2012 8:32 pm    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

Dear jacob alex,
'short/long' arms are equivalent to 'mobile fulcrum along the seesaw rod'.
You have just to keep the weights equal, and install the fulcrum on a pin rotating around an axle.


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iacob alex
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PostPosted: Wed Jun 20, 2012 9:12 pm    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

Cher P_F !

Try to simplify the things...

You say:"...a mobile fulcrum along the seesaw rod..."

I say:use the very old/"classic" design of the Middle Ages (a hinged end/0*-180*)...including MT13

So,we have so easy the bottom "self",due to gravity hanging.

Remains to solve/imagine/test the second (top) self:a quick jump,"supplied" by gravity impetus/momentum "via" rotational inertia.

The "puzzle" of a possible PM device,for the moment, moves in a single (top) point:imagine a "self" (short arm must "jump" as a long arm).

All the best! / Alex



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PostPosted: Fri Jun 22, 2012 4:17 pm    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

Sounds good Iacob - just design so anything going down counterbalanced by something going up. Vertical com of the overall system must never change. Overbalancing without commutation gives you a balanced wheel or keeling followed by balance.

We can think of this like a battery. As long as the poles (+,-) are separated, we have PE. Shorting our poles together is like our wheel keeling followed by balance.

Commutating our wheel is just like keeping our battery poles separated (binary system).

Keep in mind when we have binary separation, we are dealing with four separate PE fields; vertical lift, vertical descent, rotational lift, rotational descent. All we do is build inertia in one field then trap it in another with a "quick jump".


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iacob alex






PostPosted: Sat Jun 23, 2012 6:29 pm    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

Hi P_F !

You said: "...short/long arms are equivalent to mobile fulcrum along the see-saw rod."

I say:
-we have two fixed bearings(one for the lever,one for the variable arm)
-we can play Milkovic's arrangement ,if we replace his swinging pendulum,with a rotating variable counterweighted pendulum ("leveraged" pendulum ).

So ,we can play as "swinging sticks" or as a "modified" Milkovic...

The basic idea is the same:variable leverage...

All the best ! / Alex


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PostPosted: Wed Jun 27, 2012 1:42 am    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

This is great Iacob, I’m glad you’re still thinking about commutation and variable leverage. If we watch enough WOD clips we can figure this out!

OK so looking at MT138, we can get a big hint. We need to keep something big parallel to something else. He shows if we do that we can get four power impulses for every turn of the wheel. How can we organize the weight paths so that we can bypass the law of levers and at the same time never change the vertical com of the system?

What simple systems can we use from side to side that will provide us with different torque values at the hub? How can we use variable leverage to build inertia in the descent system and then trap it before the system keels?

How can we transfer the weights from the lifting mechanism to the descent mechanism smoothly so a weight is always attached to one side or the other but never both at once?

Why is a binary system necessary? What does having a binary system actually mean for us?

Why does commutation of the weights result in a binary system?

What simple mechanisms might a clockmaker use to commutate and latch the weights to the short and long arms?


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iacob alex






PostPosted: Wed Jun 27, 2012 6:46 am    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

Hi Cloud!

You are focusing about MT138...

My application was related to MT13 (see "MT13 digest..." topic).

As I said many times,if we play the lever concept the "PM problem" is minimized:we need two length commutations,only.

The first one(the bottom position) is solved (Middle Ages designs...).

The second one (for the top position) needs to be solved,in some manner...

All the best ! / Alex


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iacob alex






PostPosted: Thu Jul 12, 2012 2:59 pm    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

.....for statics,you can see and think about it, at:

http://www.youtube.com/watch_popup?v=jJrzIdDUfT4&vq=medium

It's a nice performance in gravity and inertia:fulcrum (stabile,mobile...as Alexander Calder"s dynamic sculptures and a serial of levers)

Why not use the binary/lever concept for dynamics? (more precisely,for our topic)

All the best! / Alex


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iacob alex






PostPosted: Sat Jul 21, 2012 12:01 pm    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

....for an "unclear" magneto-mechanical rotation,you can find at:

http://www.youtube.com/watch?v=-ibSwX8mN6E&feature=relmfu

Maybe,big shots are only little shots who keep shooting...

All the best! / Alex


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iacob alex






PostPosted: Tue Jul 24, 2012 12:05 pm    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

.....can be a persuading reason to start your self-evident test.

You can simplify the up-here youtube game :we keep the "bumping" magnet (stator),but we can play with a single rotating magnet (rotor).

We must arrange the variable leverage:

-the "hinged magnet" will play on-off (short arm-long arm).

-the "bumping magnet" will play for the top position,to commute short arm into a long one.

All the best! / Alex


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iacob alex






PostPosted: Fri Dec 07, 2012 9:39 pm    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

.....this time,'...designed for infinite fluid motion" by Kirk Hunter ,at:

www.youtube.com/watch?v=iGRDD6rX_cQ

This superb kinetic sculpture uses the binary/lever concept for dynamics .

All the Best! / Alex


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broslad
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PostPosted: Sat Dec 08, 2012 7:52 am    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

Do you think the prime movers operated around the axle were they would have the least affect on the balance of the wheel and the reason the wheels were so big is because the shifter weights had to be as far away from them to have the most affect.


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iacob alex






PostPosted: Sat Dec 08, 2012 8:42 am    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

Hi !
The "'prime" (and only!) mover is the permanent motion of the air: all kind of these works of art are called "kinetic sculptures".

The artistic impression is the leagage/foliage of a tree and the small,unseen motion of the air :there are no hidden spare parts("movers") !

So,we have a natural model with a tinyl "input",with an impressive "output",transfigured by a skilled artist.

If you type on internet this label , you can find a lot of them.

All the Best! / Alex


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PostPosted: Sat Dec 08, 2012 9:24 am    Post subject: re: A binary solution ?!... Reply with quote Report Post to Admin

broslad,

The factors of a mass being further from the centre of rotation:

Increased inertia (takes more energy to speed and slow the wheel)
Increased CF (Related to inertia)
Increased energy for given rotational speed

If you shift a weight vertically 10cm, it will give the same rotational energy to the wheel, regardless of its location and radius on the wheel.


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