Re: Thoughts...


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Posted by Scott Ellis (216.87.95.64) on April 10, 2002 at 20:59:55:

In Reply to: Re: Thoughts... posted by L. P. Marken on March 16, 2002 at 10:32:16:

Hi Lars, thanks for your post. Sorry for the LONG delay...

At the far left and right points of the swing path, the kinetic energy (motion) part of the equation is exactly zero. (As a pendulum swings, it has zero velocity at the end points of the swing, where all of the energy is potential.) That means that holding the weight still at the end point and releasing it will cause it to follow the swing path. That means it will soon arrive at a point more than 3 times higher than it was first lifted.

I have verified that the behavior is the same (only in reverse) no matter whether the weight is lifted straight (or pulled straight down), or deviated aside and released.

Best,
Scott

: About the swinging Spring:

: To achieve the pattern described, one cannot simply release the weight at any point long the trajectory. One would also have to give it the speed and direction it would normally have at that point of the trajectory. I think :-)




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