Can you help me with some math?

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Posted by Will Green (64.109.36.6) on October 11, 2003 at 17:35:49:

Hello

My name is Will Green I have a new motor design and the math has me perplexed. I am looking for third party verification as to the validity of the math as applied to this mechanical system. Can you please help me or refer me to some one who can?

Sincerely
Will Green
(920) 707-2511

Engine Math

In a fluid embodiment, this motor is 14 diameter, 8 cylinders, 2 pistons, with a 7 dia. crank shaft and 0.5 displacement, there are 3 active cylinders. In this example we are using the constants 450 psi cylinder pressure, rotating at 900 rpm. The above system is driven by a hydraulic fluid pump with an electric motor.

Constants

Displacement = 1/2 inch

Pistons = 2 diameter

Active Cylinders = 3

Starwheel Crankshaft = 7 diameter

Pressure = 450 PSI

Speed = 900 RPMs

A = Cylinder Area = pi*(r^2) = 3.14*(1*1) = 3.14

Ta = Total Area = A*active cylinders = 3.14*3 = 9.42

P = Pressure = 450psi

F = Foot Pounds = ft lbs = (crankshaft radius / 12)*4239 = (3.5/12) =.2916 * 4,239 = 1,236 ft lbs

F1 = Ta*P = 9.42*450 = 4,239 in second HP formula

C = Circumference of Star wheel = 7 * 3.14159 = 21.99

N = RPM = 900

D = Distance in 1 Min = (C*N) /12 = (21.99*900) /12 = 19,791in/12 = 1,649.25 ft

L = Starwheel Crankshaft Radius / 12 inches = 3.5/12 = .29 ft

With the above given; the following is 2 different HP formulas for work out:

1.) HP=F*N/5252 = 211.8 HP or = 158,002 W

2.) HP=(C*N / 12/60) * F1 / 550 =211.85 HP or = 158,040 W

What we need to do now that we have calculated the above HP formulas, we then calculate pump fluid flow & HP based on a volume of 12.56 cu in per rev || 900 rpm then convert that into gal per min, and use the above pressure at 450 psi

The total displacement per cylinder = Cylinder Area* Displacement - 1.57 cubic inches

The total displacement per rev = Cubic Inches* 8 Cylinders = 3.14*0.5*8 = 12.56 displacement per rev.

Total Displacement at speed = Displacement per rev* RPM = 12.56 * 900 rpm = 11,304 total displaced cubic inches

GPM = Total Displacement Cubic Inches / GPM Constant = 11304 Cu In / 231 = 48.93 GPM

With 48.93 GPM and a pressure of 450 psi we can compute pump HP work in.

The following are 2 Hydro HP formulas representing work in.

1.) PUMP HP=GPM*P / 1714 = 48.93 * 450 /1,714 =12.84HP or = 9,578.64 W

2.) PUMP HP=GPM*P*.0007 = 48.93 * 450 * 0007 = 15.41 HP or = 11,495.86 W

Efficiency work out / work in * 100 = 211.98HP / 15.41 HP * 100 = 1,374.56%

The efficiency of a machine, which is defined as the ratio of the work output to the work input, is always less than one, since some of the input is invariably wasted in overcoming friction. The element of time does not enter into the computation of work; the time rate of doing work is called power

The ability of a machine to amplify force is called its Mechanical Advantage. In this situation, the force is increased by a factor of 9.42. Mathematically, the mechanical advantage (MA) is equal to the force exerted by the machine (resistance force - Fr) divided by the force input (effort force - Fe). Thus the equation for mechanical advantage is:

MA = Fr / Fe

Fr = 4239

Fe = 450

MA = 4,239 / 450 = 9.42

Mechanical advantage is the ratio of output force divided by input force.

If the output force is bigger than the input force, a machine has a mechanical advantage greater than one.

Math references

These formulas are courtesy of Gulf Coast Air & Hydraulics Lion Hydraulics

Reference 1 http://www.gulfcoastairandhyd.com/formulas.htm

Reference 2 Courtesy of Sidener Engineering http://www.sidenereng.com/formulas.htm

Reference 4 Efficiency formulas http://www.kent.k12.wa.us/staff/trobinso/physicspages/PhysicsOf/Wade/physics.htm http://www.reliance.com/prodserv/motgen/b7087_5/b7087_5_3.htm http://www.zoeller.com/zep/techbrief/JF1article.htm

Reference 5 Pump HP formulas see http://www.hfsindustrial.com/formulas/formulas.htm

Reference 6 HP and volumetric efficiency Combinations in Sliding Contact", NASA TM-106348, DOE/NASA/50306-3, N94-15769, October 1993.
Nobel Laureate Richard Feynman and one of Einstein's protégés, John Wheeler, have calculated that there is more than enough energy in the volume of a coffee cup to evaporate all the world's oceans!

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Re: Can you help me with some math? Jonathan 03:51:37 10/12/03 (0)

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Comments:	: : Hello : My name is Will Green I have a new motor design and the math has me perplexed. I am looking for third party verification as to the validity of the math as applied to this mechanical system. Can you please help me or refer me to some one who can? : Sincerely : Will Green : (920) 707-2511 : : Engine Math : In a fluid embodiment, this motor is 14” diameter, 8 cylinders, 2” pistons, with a 7” dia. crank shaft and 0.5” displacement, there are 3 active cylinders. In this example we are using the constants 450 psi cylinder pressure, rotating at 900 rpm. The above system is driven by a hydraulic fluid pump with an electric motor. : : Constants : Displacement = 1/2” inch : Pistons = 2” diameter : Active Cylinders = 3 : Starwheel Crankshaft = 7” diameter : Pressure = 450 PSI : Speed = 900 RPM’s : : A = Cylinder Area = pi(r^2) = 3.14(11) = 3.14” : Ta = Total Area = Aactive cylinders = 3.143” = 9.42” : P = Pressure = 450psi : F = Foot Pounds = ft lbs = (crankshaft radius / 12)4239 = (3.5/12) =.2916 * 4,239 = 1,236 ft lbs : F1 = TaP = 9.42450 = 4,239 in second HP formula : C = Circumference of Star wheel = 7 * 3.14159 = 21.99 : N = RPM = 900 : D = Distance in 1 Min = (CN) /12 = (21.99900) /12 = 19,791in/12 = 1,649.25 ft : L = Starwheel Crankshaft Radius / 12 inches = 3.5/12 = .29 ft : With the above given; the following is 2 different HP formulas for work out: : 1.) HP=FN/5252 = 211.8 HP or = 158,002 W : 2.) HP=(CN / 12/60) * F1 / 550 =211.85 HP or = 158,040 W : What we need to do now that we have calculated the above HP formulas, we then calculate pump fluid flow & HP based on a volume of 12.56 cu in per rev \|\| 900 rpm then convert that into gal per min, and use the above pressure at 450 psi : The total displacement per cylinder = Cylinder Area* Displacement - 1.57 cubic inches : The total displacement per rev = Cubic Inches* 8 Cylinders = 3.140.58 = 12.56 displacement per rev. : Total Displacement at speed = Displacement per rev* RPM = 12.56 * 900 rpm = 11,304 total displaced cubic inches : GPM = Total Displacement Cubic Inches / GPM Constant = 11304 Cu In / 231 = 48.93 GPM : With 48.93 GPM and a pressure of 450 psi we can compute pump HP work in. : The following are 2 Hydro HP formulas representing work in. : 1.) PUMP HP=GPMP / 1714 = 48.93 450 /1,714 =12.84HP or = 9,578.64 W : 2.) PUMP HP=GPMP.0007 = 48.93 * 450 * 0007 = 15.41 HP or = 11,495.86 W : : Efficiency work out / work in * 100 = 211.98HP / 15.41 HP * 100 = 1,374.56% : The efficiency of a machine, which is defined as the ratio of the work output to the work input, is always less than one, since some of the input is invariably wasted in overcoming friction. The element of time does not enter into the computation of work; the time rate of doing work is called power : : The ability of a machine to amplify force is called its Mechanical Advantage. In this situation, the force is increased by a factor of 9.42. Mathematically, the mechanical advantage (MA) is equal to the force exerted by the machine (resistance force - Fr) divided by the force input (effort force - Fe). Thus the equation for mechanical advantage is: : MA = Fr / Fe : Fr = 4239 : Fe = 450 : MA = 4,239 / 450 = 9.42 : Mechanical advantage is the ratio of output force divided by input force. : If the output force is bigger than the input force, a machine has a mechanical advantage greater than one. : : Math references : These formulas are courtesy of Gulf Coast Air & Hydraulics Lion Hydraulics : Reference 1 http://www.gulfcoastairandhyd.com/formulas.htm : Reference 2 Courtesy of Sidener Engineering http://www.sidenereng.com/formulas.htm : Reference 3 MacDizzy© 1993-1999 http://www.macdizzy.com/formulas.htm : Reference 4 Efficiency formulas http://www.kent.k12.wa.us/staff/trobinso/physicspages/PhysicsOf/Wade/physics.htm http://www.reliance.com/prodserv/motgen/b7087_5/b7087_5_3.htm http://www.zoeller.com/zep/techbrief/JF1article.htm : Reference 5 Pump HP formulas see http://www.hfsindustrial.com/formulas/formulas.htm : Reference 6 HP and volumetric efficiency http://www.prestage.com/carmath/formulas.asp : Published REFERENCES : Dale, T.W.,"Spherical Piston Radial Action Engine", U.S. Patent #5,419,288, May 30, 1995. : Avallone, E.A. and Baumeister, T. III,"Marks' Standard Handbook for Mechanical Engineers", Ninth edition, McGraw-Hill, New York, 1987. : Richards, T.D.,"The Hanes Engine", informational report, copyright 1994, available from the author at P.O. Box 21147, Carson City, NV, 89721. : Ashley, S.,"A New Spin on the Rotary Engine", Mechanical Engineering, April 1995, p80-82. : Bloch, H.P.,"A Practical Guide to Compressor Technology", McGraw-Hill, New York, 1996. : Anon.,"GAUSS Volume I, System and Graphics Manual", Aptech Systems, Inc., Maple Valley, WA, July 18, 1994. : Heywood, J.B.,"Internal Combustion Engine Fundamentals", Mcgraw-Hill, New York, 1988. : Sliney, H.E. and Dellocorte, C.," The Friction and Wear of Ceramic/Ceramic and Ceramic/Metal Combinations in Sliding Contact", NASA TM-106348, DOE/NASA/50306-3, N94-15769, October 1993. : Nobel Laureate Richard Feynman and one of Einstein's protégés, John Wheeler, have calculated that there is more than enough energy in the volume of a coffee cup to evaporate all the world's oceans! :
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